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已知2sin(3π+θ)=cos(π+θ),求2sin^2 θ+3sinθcosθ-cos^2 θ
人气:290 ℃ 时间:2020-04-10 03:13:21
解答
2sin(3π+θ)=cos(π+θ)2sinθ=cosθtanθ=1/22sin^2 θ+3sinθcosθ-cos^2 θ2sin^2 θ+3sinθcosθ-cos^2 θ___________________________=____________________________=1...
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