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求与双曲线9分之x2-16分之y2=1有共同渐近线且经过点M(-3 4根号3)的双曲线标准方程.
人气:354 ℃ 时间:2019-10-19 15:16:06
解答
一条渐近线方程为y=(3/4)x设双曲线 a=3m,则焦点在x轴,b=4m;a=4n,则焦点在y轴,b=3nx^2/9m^2-y^2/16m^2=1 =>9/9m^2-48/16m^2=1=>-2=m^2 =>m无解y^2/16n^2-x^2/9n^2=1 =>48/16n^2-9/9n^2=1=...
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