∵f(x)=sin^2x+sinxcosx
=(1-cos2x)/2+1/2sin2x
=1/2(sin2x-cos2x)+1/2
=√2/2sin(2x-π/4)+1/2
∴当sin(2x-π/4)=-1时
f(x)min=（1-√2）/2
当sin(2x-π/4)=1时
f(x)max=（1+√2）/2