解下面的三元一次方程组 2x+6y+8z=6 ① ,3x—12y+7z=—3 ② ,4x—3y+4z=11 ③
要详细过程啊
人气:253 ℃ 时间:2019-10-23 05:36:16
解答
2x+6y+8z=6 (1)
3x—12y+7z=—3 (2)
4x—3y+4z=11 (3)
(1)+(3)*2
10x+16z=28
5x+8z=14 (4)
(1)*2+(2)
7x+23z=9 (5)
(5)*5-(4)*7
115z-56z=45-98
59z=-53
z=-53/59
x=(9-23z)/7=250/59
y=(3x+7z+3)/12=139/177
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