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cos1°+cos2°+cos3°+...+cos180°的值为?到底是0还是-1?
人气:129 ℃ 时间:2020-06-12 08:48:25
解答
cos1°+cos2°+cos3°+……+cos180°
=(cos1°+cos179°)+(cos2°+cos178°)+(cos3°+cos177°)+……+(cos89°+cos91°)+cos90°+cos180°
=(cos1°-cos1°)+(cos2°-cos2°)+(cos3°-cos3°)+……(cos89°-cos89°)+cos90°-cos0°
=0-1
=-1
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