若4X﹣3Y-6Z=0,X+2Y-7Z=0,(XYZ不等于0),求(5X^2+2Y^2-Z^2)/(2X^2-3y^2-10Z^2)的值?
人气:173 ℃ 时间:2019-08-18 04:47:33
解答
4X﹣3Y-6Z=0 (1) X+2Y-7Z=0 (2) (1) - (2) * 4 ==> -11y + 22z = 0 ==> y = 2Z (1) * 2 + (2) * 3 ==> 11x - 33z =0 ==> x = 3Z (5X^2+2Y^2-Z^2)/(2X^2-3y^2-10Z^2) = [5 * (3z)^2 + 2 * (2z)^2 - z^2)] / [ (2 * (...
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