化简[sin(π-α)cos(3π-α)tan(-α-π)]/[tan(4π-α)sin(5π+α)]_数学解答

化简[sin(π-α)cos(3π-α)tan(-α-π)]/[tan(4π-α)sin(5π+α)]

人气：399 ℃　时间：2020-04-04 22:49:16

解答

sin(π-a)cos(3π-a)tan(-π-a)tan（a-2π）/tan(4π-a）sin(5π+a)
=sinacosatana/tanasina
=cosa