1、当n=1时,a1=s1=2当n≥2时,an=Sn-S(n-1)=4n²-2n-[4(n-1)²-2(n-1)]=8n-6当n=1时,满足an通项公式∴an=8n-6 n属于N+2、∵an=2(log2)bn∴(log2)bn=4n-3即bn=2^(4n-3)当n=1时,bn=2∴bn是以2为首项,2^4为公比...