已知向量a=(cosa,sina),向量b=(cosβ,sinβ)(0
人气:477 ℃ 时间:2019-10-24 03:57:05
解答
(1)|a|=√[(cosa)^2+(sina)^2]=1
(2) 证明
向量(a+b)*向量(a-b)
=a^2-b^2
=|a|^2-|b|^2=1-1=0
所以a+b与a-b互相垂直
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