已知函数y=-3x^3+6x^2+m的极大值为13,则m为_
不好意思,是y=-x^3+6x^2+m
人气：287 ℃ 时间：2020-04-29 10:50:35
解答
Y=-3x^3+6x^2+m
y'=-9x^2+12x=-9(x-2/3)^2+4
所以当x=2/3时,达到极大值13,即：
f(2/3)=13
-3*(2/3)^3+6*(2/3)^2+m=13
m=13.
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