∵△ABC是等边三角形,∴∠ACB＝60°,AB＝BC,又AD＝CD,∴AD⊥CD,∴∠DAE＝30°.∵CD＝CE,∴∠CDE＝∠CED,∴∠ACB＝∠CDE＋∠CED＝2∠CED,∴∠CED＝∠ACB/2＝60°/2＝30°,结合证得的∠DAE＝30°,得：∠DBE＝∠DEB,∴B...