两边分别通分得
(13x-39-10x+40)/(x-4)(x-3)=(4x-4-x+5)/(x-5)(x-1)
(3x+1)/(x-4)(x-3)=(3x+1)/(x-5)(x-1)
∴3x+1=0 或(x-5)(x-1)=(x-4)(x-3)
x=-1/3 x²-6x+5 =x²-7x+12
x=7
检验：x=-1/3,x=7是方程的解