Mm0 |
r2 |
4π2 |
T2 |
得:M=
4π2r2 |
GT2 |
4π2c3t03 |
GT2 |
设地球半径为R,则地面上质量为m′的物体的重力近似等于物体与地球的万有引力,故有:F引′=m′g,
即:G
mm′ |
R02 |
得:m=
gR02 |
G |
所以有:
M |
m |
4π2c3t03 |
gR02T2 |
答:太阳质量M与地球质量m之比为
4π2c3t03 |
gR02T2 |
Mm0 |
r2 |
4π2 |
T2 |
4π2r2 |
GT2 |
4π2c3t03 |
GT2 |
mm′ |
R02 |
gR02 |
G |
M |
m |
4π2c3t03 |
gR02T2 |
4π2c3t03 |
gR02T2 |