> 数学 >
化简√3sin(-1200°)tan11π/6-cos585°tan(-37π/4)=
人气:413 ℃ 时间:2020-06-30 12:21:45
解答
原式
=√3sin(-1200°+360°*3)*tan(11π/6-2π) - cos(585°-360°*2)tan(-37π/4 +10π)
=√3sin(-120°) *tan(-π/6) - cos(-135°) *tan(3π/4)
=√3 * (-√3/2) *(-√3/3) -√2 /2 * 1
= -√3/2 -√2/2
推荐
猜你喜欢
© 2026 79432.Com All Rights Reserved.
电脑版|手机版