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设f(x)在x0可导,则
lim
x→0
f(x0+x)−f(x0−3x)
x
等于(  )
A. 2f'(x0
B. f'(x0
C. 3f'(x0
D. 4f'(x0
人气:176 ℃ 时间:2020-09-14 07:53:40
解答
∵f(x)在x0可导,∴f′(x0)=limx→0f(x0+x)−f(x0)x.∴limx→0f(x0+x)−f(x0−3x)x=limx→0f(x0+x)−f(x0)+f(x0)−f(x0−3)x=limx→0f(x0+x)−f(x0)x+limx→0f(x0−3x)−f(x0)−x  =f′(x0)+3limx→0f(x...
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