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3x^2-x^2y+y^2=-3,求dy/dx
人气：465 ℃　时间：2019-10-11 08:22:14
解答
F(x,y)=3x^2-x^2y+y^2+3=0
dy/dx=-Fx/Fy
=-(6x-2xy)/(-x^2+2y)=(6x-2xy)/(x^2-2y)
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