(2ab^2\a+b)^3除以(ab^3\a^2-b^2)^2乘以(a+b\a^2-2ab+b^2)
=[8a³b^6/(a+b)³]÷[a²b^6/(a+b)²(a-b)²]×[(a+b)/(a-b)²]
=[8a³b^6(a+b)²(a-b)²(a+b)] / [a²b^6(a+b)³(a-b)²]
=8a
当a=2 b=-3时,原式=8×2=16