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利用因式分解计算(要写过程)
99*101*10001
49(a-b)^2-16(a+b)^2
2x^2-1/2y^2
人气:404 ℃ 时间:2020-02-03 22:28:17
解答
99*101*10001 =(100-1)(100+1)*10001 =(100^2-1)*10001=(100^2-1)(100^2+1) =100^4-1 =9999999949(a-b)^2-16(a+b)^2 =[7(a-b)+4(a+b)][7(a-b)-4(a+b)] =(11a-3b)(3a-11b)2x^2-1/2y^2=2(x^2-1/4y^2 ) =2(x+1/2y)(x-1/...
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