> 数学 >
∫cos^2(wt+φ)dt
人气:356 ℃ 时间:2020-03-31 09:22:31
解答
∫cos^2(wt+φ)dt=∫(cos(2wt+2φ)+1)/2dt
=t/2+1/2*∫cos(2wt+2φ)dt
=t/2+1/(4w)sin(2wt+2φ)+C,C为任意常数.
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版