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∫ln(1+x²)/x³dx的不定积分
人气:221 ℃ 时间:2019-12-21 00:42:51
解答
∫ln(1+x²)/x³dx= -1/2∫ln(1+x²)d(1/x²)=-1/2(ln(1+x²))/x²)+1/2∫1/(x²(1+x²))dx²=-1/2(ln(1+x²))/x²)+1/2∫(1/x²-1/(1+x²))dx...
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