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f(x)=根号下(1+sinx)+根号下(1-sinx)值域.
人气:476 ℃ 时间:2019-10-25 23:32:39
解答
定义域是R
y>=0
y^2=1+sinx+1-sinx+2√(1-sinx)(1+sinx)
=2+2√[1-(sinx)^2]
=2+2√(cosx)^2
=2+2|cosx|
0<=|cosx|<=1
0<=2|cosx|<=2
2<=2+2|cosx|<=4
2<=y^2<=4
y>=0
√2<=y<=2
值域[√2,2]
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