题目应为【若奇函数f(x) = (px^2+3)/(3x-q),且f(2)=5/2,求实数p,q的值】
∵奇函数,所以f(-x)=-f(x)
(px^2+3)/(-3x-q) = - (px^2+3)/(3x-q)
1/(-3x-q) = - 1/(3x-q)
-1/(3x+q) = - 1/(3x-q)
3x+q = 3x-q
q=-q
q=0
f(x) = (px^2+3)/(3x)
f(2)=5/2
(4p+3)/6 = 5/2
4p+3=15
4p=12
p=3