延长ac,过b作bo垂直于ac过c作cd垂直于ab
sina=ob/ab=1/3
ob=1/3ab
sinocb=ob/cb=(1/3ab)/(2/3ab)=1/2
所以ocb=30
所以c=150
设ob=k
oc=√3k
ao=2√2k
cd=ac*sina=(2√2-√3)k/3
sinb=cd/cb=cd/2k=(2√2-√3)/6