若对于一切实数x,1-2sin方x=acos方x+bcosx+c恒成立那么a方+b方+c方等于
人气:419 ℃ 时间:2020-03-31 01:43:03
解答
1-2sin²x=acos²x+bcosx+c
1-2(1-cos²x)=acos²x+bcosx+c
2cos²x-1=acos²x+bcosx+c
恒成立
所以a=2,b=0,c=-1
所以a²+b²+c²=5
推荐
- 设a,b,c为实数且cos2x=acos^2x+bcosx+c恒成立,则a^2+b^2+c^2=
- 若对于一切实数x,1-2sin²x=ɑcos²x+bcosx+c恒成立,那么a²+b²+c²=
- 求实数a的取值范围使得对任意实数X和任意Q∈[0,π/2]恒有x+3+2sinθcosθ方+x+asinθ+aCOSθ方≥1/8
- 两不相等实数a,b,满足下列关系式:a^2sinθ+acosθ-(π/4)=0,b^2sinα+bcosα-(π/4)=0
- 已知函数f(x)=2sin(2x+φ)对任意的实数恒有f(π/3-x)=f(π/3+x)成立
- 鱼虱子为什么能浮在水面上?请用物理知识回答.
- 味觉和嗅觉感受器均感受什么信息,两者相互影响形成味觉
- After having been wounded towards the end of the war,he had been sent to hospital and was separated from his unit.
猜你喜欢