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数学
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x^3-4xy+4y^2分之x^2-4y^2,其中x=5,y=-1 先求值,再化简 急用!
人气:377 ℃ 时间:2020-05-15 02:08:05
解答
x^3会不会打错了
是不是x^2-4xy...
原式=(x^2-4y^2)/(x^2-4xy+4y^2)
=(x+2y)(x-2y) / (x-2y)^2
=(x+2y)/(x-2y)
=(5-2*1)/(5+2*1)
=3/7是我打错了,呵呵。太着急了 你怎么知道我打错了?x^3-4xy+4y^2无法分解啊换成x^2就可以了
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