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化简求值:(4y^2-x^2)/(-x^2-4y^2+4xy),其中x=1,y=-3/2
人气:311 ℃ 时间:2020-05-19 12:42:50
解答
:(4y^2-x^2)/(-x^2-4y^2+4xy),
=(2y+x)(2y-x)/[-(2y-x)^2]
=(2y+x)/(x-2y)
=(-3+1)/(1+3)
=-1/2
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