f（x）＝cos²（x＋12分之π）＋½·sin2x＋1=(1+cos(2x+π/6))/2+1/2sin2x+1=1/2(cos(2x+π/6)+sin2x)+3/2=1/2(cos2x根号3/2-sin2x1/2+sin2x)+3/2=1/2(cos2x*根号3/2+sin2x*1/2)+3/2=根号3/2sin(2x+π/3)...