思路：把圆的方程写成标准式,根据R²＞0即可求出m的范围.因为x²+y²+(1-m)x+1=0故：[x+(1-m)/2] ²+ y²=[(1-m)/2] ²-1故：[(1-m)/2] ²-1＞0故：[(1-m)/2-1] [(1-m)/2+1] ＞0故：m＞...