如图,∠ACD是△ABC的外角,∠ABC的平分线与∠ACD的平分线交于点A
1,∠A
1BC的平分线与∠A
1CD的平分线交于点A
2,…,∠A
n-1BC的平分线与∠A
n-1CD的平分线交于点An.设∠A=θ.则:

(1)∠A
1=______;
(2)∠A
n=______.
(1)∵A1B是∠ABC的平分线,A1C是∠ACD的平分线,∴∠A1BC=12∠ABC,∠A1CD=12∠ACD,又∵∠ACD=∠A+∠ABC,∠A1CD=∠A1BC+∠A1,∴12(∠A+∠ABC)=12∠ABC+∠A1,∴∠A1=12∠A,∵∠A=θ,∴∠A1=θ2;(2)同理...