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数学
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设函数f(x)=-1/3x~3+2ax~2-3a~2x+1(0
人气：410 ℃ 时间：2019-10-05 02:27:29
解答
答：
(1).
f'(x)=-x^2+4ax-3a^2=-(x-a)(x-3a),其中(0
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