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若n2+n-1=0,则n3+2n2+2008=___
人气:471 ℃ 时间:2020-01-24 20:26:13
解答
∵n2+n-1=0,
∴n3+2n2+2008
=n(n2+n-1)+(n2+n-1)+2009
=0+0+2009
=2009.
故答案为:2009.
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