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数学
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设f(x)=a^X-1/2,若f(lga)=根号10,求a的值
人气:112 ℃ 时间:2019-08-19 22:55:12
解答
f(lga)=√10,
a^( lga -1/2) =√10,两边取对数得:
lg(a^( lga -1/2))=lg√10,
( lga -1/2)lga=1/2
( 2lga -1)lga=1
2lg²a- lga-1=0
lga=1或-1/2
a=10或√10/10.
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