有题意得：x≠14,2,6log2[(x-14)(x-2)]=3+log2(6-x)=>log2[(x-14)(x-2)]-log2(6-x)=3=>[(x-14)(x-2)]/(6-x)=2^3=>(x^2-16x+28)/(6-x)=8=>x^2-16x+28=48-8x=>x^2-8x-20=0=>x=10或x=2(舍去)