f(x)=x的平方-2(m+2)x+m的平方-1=0
判别式=4(m+2)^2-4m^2+4>0
4m^2+16m+16-4m^2+4>0
16m>-20
m>-5/4
0f(0)>0
m^2-1>0
m<-1 or m>1
f(1)<0
1-2m-4+m^1-1<0
m^2-2m-4<0
1-根号5-5/41m>-1判别式=4(m+2)^2-4m^2+4>04m^2+16m+16-4m^2+4>016m>-20m>-5/4f(1)>0m<1-根号5 or m>1+根号5取交集，m>1+根号5