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当-π/2≤x≤π/2时,函数fx=2sin(x+π/3)的最大值、最小值是多少
人气:204 ℃ 时间:2020-05-11 10:05:23
解答
-π/2 ≤ x ≤ π/2
-π/2 + π/3 ≤ x + π/3 ≤ π/2 + π/3
-π/6 ≤ x + π/3 ≤ 5π/6
-1/2 ≤ sin(x + π/3) ≤ 1
-1 ≤ 2sin(x + π/3) ≤ 2
-1 ≤ f(x) ≤ 2
最大值是 2
最小值是 -1
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