如果有理数a,b满足|ab-2|+(1-b)平方
试求1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+...+1/(a+2006)(b+2006))
人气:246 ℃ 时间:2019-08-26 06:48:36
解答
你的题目不完整,应该是少个=0吧
那样就可以求得ab=2 1-b=0
a=2,b=1
这样答案就为1/1*2+1/2*3+.1/2007*2008
=1-1/2+1/2-1/3+.-1/2008
=2007/2008
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