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解方程:x的log以2为底x的对数=32x的4次
人气:437 ℃ 时间:2019-10-17 06:53:35
解答
x^[log2(x) -4]=32x^4x^[log2(x) -4]=2^5log2(x) -4=log2(2^5) / log2(x) =5/log2(x)[log2(x)]^2 -4log2(x) -5=0[log2(x) -5][log2(x) +1] =0log2(x) =5 ====> x=2^5或者log2(x)=-1 ====> x=1/2
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