已知tanx=2,求(2cos^2 x/2-sinx-1)/(sinx+cosx)
人气:241 ℃ 时间:2019-10-19 08:33:28
解答
原式=[cos(2*x/2)-sinx]/(sinx+cosx)
=(cosx-sinx)/(sinx+cosx)
上下除cosx
=(1-sinx/cosx)/(sinx/cosx+1)
=(1-tanx)/(tanx+1)
=-1/3
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