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(Log2)的三次方+(Log5)的三次方+lg8*lg5
人气:298 ℃ 时间:2020-05-01 04:46:41
解答
(lg2)^3+(lg5)^3+lg8*lg5
=(lg2+lg5)((lg2)^2-lg2*lg5+(lg5)^2)+3lg2*lg5
=(lg2)^2+2lg2*lg5+(lg5)^2
=(lg2+lg5)^2=1
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