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数学
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若sina+cosa=m,求sin2a-cos4a的值
人气:356 ℃ 时间:2020-05-27 19:04:14
解答
sin2a-cos4a=sin2a - 1 + 2sin²2asina + cosa =msin²a +cos²a + 2sinacosa =m²1+2sinacosa =m²sin2a = m² -1所以:sin2a-cos4a=sin2a - 1 + 2sin²2a=m²-1 -1 + 2 m^4 + 4m&...
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