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计算:(m^2+n^2)^2-4m^2n^2
人气:357 ℃ 时间:2020-04-11 15:19:15
解答
(m^2+n^2)^2-4m^2n^2
=m^4+n^4+2m^2n^2-4m^2n^2
=m^4+n^4-2m^2n^2
=(m^2-n^2)^2
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