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若m^2+n^2-n+4m+17/4=0,m=____,n=_____
计算:(1)(2x-3y)^2-(3x+y)(3x-y)
(2)(x+y)(x^2+y^2)(x-y)
(3)(m-n-3)^2
人气:421 ℃ 时间:2020-06-02 04:31:54
解答
m²+n²-n+4m+17/4=0(m+2)²+(n-1/2)²=0m=-2,n=1/2(1)=4x²-12xy+9y²-9x²+y²=-5x²-12xy+10y²(2)=(x²-y²)(x²+y&s...
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