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求不定积分∫2x-2/x^2-2x+3dx
求具体过程.
人气:110 ℃ 时间:2020-05-12 06:36:48
解答
∫2x-2/x^2-2x+3dx
=∫(x^2-2x+3)'/(x^2-2x+3) dx
=∫1/(x^2-2x+3) d(x^2-2x+3)
=ln(x^2-2x+3)+c
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