四边形ABCD中,AC垂直于BD,垂足为O,OA>OC,OD>OB,求证AB+CD>AD+BC
请2\3楼,说明白点,我不懂
人气：323 ℃ 时间：2019-08-21 12:01:01
解答
在OA上取OE=OC；在OD上取OF=OB,连接BE、EF、FC,连接AF、ED交于G
AG+GD>AD；EG+GF>EF
AG+GD+ EG+GF >AD +EF
即AF+ED> AD +EF
可知：AF=AB、DE=CD、EF=BC
所以AB+CD>AD+BC
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