x1 x2是方程2x²-6x+3=0的两个根
根据韦达定理可得
x1+x2=3
x1 * x2=3/2
所以
1/x1+1/x2
=x2/(x1*x2)+x1/(x1*x2)
=(x1+x2)/(x1*x2)
=3/(3/2)
=2