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Sn=1*1/3+3*(1/3)^2+5*(1/3)^3+.+(2n-1)*(1/3)^n=
人气:439 ℃ 时间:2020-06-25 09:42:24
解答
两边同乘33Sn=1+3*(1/3)+5*(1/3)^2+...+(2n-1)*(1/3)^(n-1)Sn = 1*(1/3)+3*(1/3)^2+...+(2n-3)*(1/3)^(n-1)+(2n-1)*(1/3)^n两式相减2Sn=1+2*(1/3)+2*(1/3)^2+...+2*(1/3)^(n-1)-(2n-1)*(1/3)^n2Sn=1-(2n-1)*(1/3)^n+...
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