(abc+1)(-abc+1)(a^2b^2c^2)
=(1+abc)(1-abc)(a^2b^2c^2)
=(1-a^2b^2c^2)(a^2b^2c^2)
=a^2b^2c^2-a^4b^4c^4多谢提醒！但答案有些错误。（a^2b^2c^2)还要加1，我算了算答案应该是1-a^4b^4c^4不用谢