已知tanα=根号2,求下列各式的值 (1)cosα-5sinα/3cosα+sinα
人气:294 ℃ 时间:2019-10-23 07:24:07
解答
tanα = √2
cosα = 1/√(1+tan²α) = √3/3
sinα = cosα tanα = √2/(√3/3) = √6
cosα-5sinα/3cosα+sinα
= cosα-5tanα/3+sinα
= √3/3 - 5√2/3 + √6
推荐
猜你喜欢
- 已知平面内三个点A(0,-3),B(3,3)C,(1,-1),则向量AB与BC的夹角为
- 从前,一个小村子里有座漂亮的花园.(缩句)
- There are still____apples in the fruit bowl,will you have another one?A.few B.little C.a few
- terribel weather we had last Sunday.
- 初三物理试题钻木取火的一种方法,将削尖的木棒伸到木板洞里
- 英语中一般什么情况用it is作形式主语开头的句型
- 除去硝酸钾晶体中混有的少量氯化钠用什么办法,原因
- 已知无穷等比数列{an}首项为1,公比为q,前n项和为Sn,求lim(Sn/Sn+1)