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数学
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若实数a,b满足
1
2
a−ab+
b
2
+2=0
,则a的取值范围是______.
人气:205 ℃ 时间:2020-02-02 21:36:46
解答
因为b是实数,所以关于b的一元二次方程
b
2
−ab+
1
2
a+2=0
,
△=(−a
)
2
−4×1×(
1
2
a+2)
≥0,
解得a≤-2或a≥4.
故答案为a≤-2或a≥4.
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