| sinx |
| 1+cosx |
y′=
| (sinx)′(1+cosx)−sinx(1+cosx)′ |
| (1+cosx)2 |
=
| cosx+cos2x+sin2x |
| (1+cosx)2 |
=
| 1+cosx |
| (1+cosx)2 |
| 1 |
| 1+cosx |
所以cosx=−
| 1 |
| 2 |
| 2 |
| 3 |
故选B.
| sinx |
| 1+cosx |
| π |
| 3 |
| 2 |
| 3 |
| π |
| 4 |
| π |
| 6 |
| sinx |
| 1+cosx |
| (sinx)′(1+cosx)−sinx(1+cosx)′ |
| (1+cosx)2 |
| cosx+cos2x+sin2x |
| (1+cosx)2 |
| 1+cosx |
| (1+cosx)2 |
| 1 |
| 1+cosx |
| 1 |
| 2 |
| 2 |
| 3 |